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Math Help Please

What are the ratios for sin A and cos A? The diagram is not drawn to scale.

Triangle Description-

AB = 29
AC = 20
BC - 21

A. sin A = 20/29, cos A = 21/29
B. sin A = 21/29, cos A = 20/21
C. sin A = 21/29, cos A = 20/29****?
D. sin A = 21/20, cos A = 20/21

Please help and explain!

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  1. Note which side is opposite to A and adjacent to A. Now review your basic trig functions. You can see that

    sinA = BC/AB
    cosA = AC/AB

    so you are correct.

    Extra credit: How did I figure it out, with no triangle to refer to?

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  2. C. sin A = 21/29, cos A = 20/19

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  3. Ratios are ratios. duh

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