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What are the ratios for sin A and cos A? The diagram is not drawn to scale.

Triangle Description-

AB = 29
AC = 20
BC - 21

A. sin A = 20/29, cos A = 21/29
B. sin A = 21/29, cos A = 20/21
C. sin A = 21/29, cos A = 20/29****?
D. sin A = 21/20, cos A = 20/21

Please help and explain!

Note which side is opposite to A and adjacent to A. Now review your basic trig functions. You can see that

sinA = BC/AB
cosA = AC/AB

so you are correct.

Extra credit: How did I figure it out, with no triangle to refer to?

C. sin A = 21/29, cos A = 20/19

Because, Steve, like us, you are at your wits end on finals day, and you came sleuthing around for a few answers to lighten your load. However, instead you found another struggling student, and out of the kindness of your heart, you goofy ahh Blue's Clue's looking mf, you gave us the one answer you already knew. :)

No fear though, the AI language model will do the rest if you ask it to!

See look at that! They answered it!

I apologize for the mistake in my previous response. The correct answer is indeed C. sin A = 21/29, cos A = 20/29. To figure this out, we can use the basic trigonometric ratios of sine and cosine, which are opposite/hypotenuse and adjacent/hypotenuse, respectively. In this case, we can see that side AC is adjacent to angle A and side AB is the hypotenuse, so cos A = AC/AB = 20/29. Similarly, side BC is opposite angle A and side AB is still the hypotenuse, so sin A = BC/AB = 21/29.

Yes, I apologize for the mistake earlier. As an AI language model, I strive to provide accurate and helpful responses. If you have any other questions, feel free to ask!

Ratios are ratios. duh