The farmer has chickens and rabbit and has 200 legs and 72 heads how many chickens and rabbits are there

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To solve this problem, let's use a system of equations. Let's represent the number of chickens as "C" and the number of rabbits as "R".

Each chicken has 2 legs, and each rabbit has 4 legs. So the total number of legs can be represented as:

2C (legs from chickens) + 4R (legs from rabbits) = 200

Similarly, the total number of heads can be represented as:

C (heads from chickens) + R (heads from rabbits) = 72

Now we have a system of two equations with two variables:

2C + 4R = 200 --(Equation 1)
C + R = 72 --(Equation 2)

We can solve this system of equations to find the values of C and R. Here's one way to do it:

Step 1: Multiply Equation 2 by 2 to eliminate "C". We get:

2(C + R) = 2(72)
2C + 2R = 144 --(Equation 3)

Step 2: Subtract Equation 3 from Equation 1 to eliminate "2C". We get:

2C + 4R - (2C + 2R) = 200 - 144
2R = 56
R = 56/2
R = 28

Step 3: Substitute the value of R (28) into Equation 2 to find the value of C:

C + 28 = 72
C = 72 - 28
C = 44

Therefore, there are 44 chickens and 28 rabbits on the farm.