IN YOUNG DOUBLE SLIT EXPERIMENT LIHGIT WAVE LENGTH 620NM is ured on 2slit are 0.3 mm interference fringes observed on the screen are 1.3 a) calculate the distance fr6 the screen and the fringd width if the distance double
To calculate the distance from the screen to the fringe width in a Young's double-slit experiment, we can use the formula:
λ = (m * d) / L
Where:
- λ is the wavelength of the light
- m is the order of the fringe
- d is the separation between the slits
- L is the distance from the slits to the screen
In this case, we are given:
- Wavelength (λ) = 620 nm = 620 x 10^-9 m
- Separation between the slits (d) = 0.3 mm = 0.3 x 10^-3 m
- Distance between the slits and the screen (L) = 1.3 m
We need to find the distance (L') from the screen to the fringe width when the distance (L) is doubled.
Let's calculate the fringe width (y) using the given values:
y = (λL) / d
Now, let's substitute the given values in the equation to find the fringe width (y):
y = (620 x 10^-9 m * 1.3 m) / (0.3 x 10^-3 m)
y ≈ 2.69 x 10^-3 m
Now, we can calculate the distance from the screen (L') when the distance (L) is doubled:
L' = 2L = 2 * 1.3 m
L' = 2.6 m
Therefore, when the distance (L) is doubled, the new distance from the screen to the fringe width (L') is approximately 2.6 m, and the fringe width remains the same at 2.69 x 10^-3 m.