Concerning compounds cyanogen, Hydrogen cyanide and sodium cyanide.
Cyanogen = C2N2 (CN)2
Hydrogen Cyanide = HCN boils at 26C and yeilds an acid solution when added with water.
Sodium Cyanide = empirical formula NaCN is a solid melts at 564C
a) Assuming that the valencies of Hydrogen, Nitrogen and Carbon in these compounds are 1,3 and 4 respectively, draw structual formulae for hydrogen cyanide and cyanogen that are consistent with these valencies
To add further detail, a pair of dots like this, : equals a bond like this -
A pair of dots = a bond like this -. I can't draw triple bonds with the computer. So dots will have to do.
H:C:::N:
:N:::C:C:::N:
In HCN, H has 1 bond, C has 4 and N has 3.
In (CN)2, N has 3 bonds and C has 4.
I hope this helps.
To draw the structural formulas for hydrogen cyanide and cyanogen, we need to understand the valencies of hydrogen, nitrogen, and carbon.
Valencies indicate the number of bonds that an element can form. In this case, hydrogen has a valency of 1, nitrogen has a valency of 3, and carbon has a valency of 4.
For hydrogen cyanide (HCN), hydrogen (H) has a valency of 1, carbon (C) has a valency of 4, and nitrogen (N) has a valency of 3. Therefore, the structural formula for hydrogen cyanide is H-C≡N, with a triple bond between carbon and nitrogen.
For cyanogen (C2N2), we have two carbons (C) and two nitrogens (N). Carbon has a valency of 4, and nitrogen has a valency of 3. Therefore, the structural formula for cyanogen is N≡C-C≡N, with a triple bond between each carbon and nitrogen.
Now, let's draw these structural formulas with dots representing the bonds:
Hydrogen cyanide (HCN):
H:C≡N
Cyanogen (C2N2):
N≡C-C≡N
I hope this helps clarify the structural formulas for hydrogen cyanide and cyanogen!