Which function contains this set of ordered pairs?
{(–2, –7), (0, 1), ( 3, –17)}
Reiny responded to this earlier, at
http://www.jiskha.com/display.cgi?id=1464879381
If you want to pin it down more, there must be some other constraints.
And here I was under the impression that I had answered this for you.
http://www.jiskha.com/display.cgi?id=1464879381
Where you actually given some functions that you did not post?
To determine which function contains the given set of ordered pairs, we need to examine the x and y values of each pair and see if there is a consistent pattern or relationship between them.
Let's go through the given set of ordered pairs:
(–2, –7): The x-value is –2 and the y-value is –7.
(0, 1): The x-value is 0 and the y-value is 1.
(3, –17): The x-value is 3 and the y-value is –17.
To find the function that contains these ordered pairs, we can start by examining the relationship between the x and y values. In this case, it appears that the y-values are changing based on some operation performed on the x-values.
If we observe carefully, we can see that the y-values are obtained by multiplying the x-values by a certain factor and then subtracting a constant value. Let's try to find this factor and constant:
From the first ordered pair, we have:
–7 = –2 * factor + constant
From the second ordered pair, we have:
1 = 0 * factor + constant
From the third ordered pair, we have:
–17 = 3 * factor + constant
Simplifying these equations, we get:
–2 * factor + constant = –7 => equation 1
0 * factor + constant = 1 => equation 2
3 * factor + constant = –17 => equation 3
By subtracting equation 2 from equation 1, we can eliminate the constant term:
–2 * factor + constant - (0 * factor + constant) = –7 - 1
–2 * factor = –8
factor = 4
Substituting the value of factor (4) into equation 2:
0 * 4 + constant = 1
constant = 1
So, the function that contains the given set of ordered pairs is y = 4x + 1.