The length of a rectangle is 15 m longer than 3 times the width. The perimeter of the rectangle is 74m .find the dimensions. answer in fractional form using mixed numbers
P=2W+2L=2w+2(15+3w)=2w+6w+30
74=8w+30
w=44/8=5 1/2
L=15+3=15+44*3/8= you do it.
is 5 one of you answers
width is 5 and 1/2
3/15 or 15/3
ay i need help iwth my home work
To find the dimensions of the rectangle, we can use the given information about its length and width and set up a system of equations based on the given conditions.
Let's assume the width of the rectangle is "w" meters.
According to the given information, the length of the rectangle is 15 meters longer than 3 times the width, which translates to:
Length = 3w + 15
The perimeter of a rectangle is calculated by adding twice the length to twice the width. We know that the perimeter is 74 meters, so we can set up the equation as:
2(length) + 2(width) = perimeter
2(3w + 15) + 2w = 74
Now, let's solve for "w" to find the width of the rectangle:
2(3w + 15) + 2w = 74
6w + 30 + 2w = 74
8w + 30 = 74
8w = 74 - 30
8w = 44
w = 44/8
w = 5.5
The width of the rectangle is 5.5 meters.
Now, substitute the value of "w" back into the equation for the length to find its value:
Length = 3w + 15
Length = 3(5.5) + 15
Length = 16.5 + 15
Length = 31.5
The length of the rectangle is 31.5 meters.
Therefore, the dimensions of the rectangle are 31.5 meters by 5.5 meters.