A survey was taken of students in math classes to find out how many hours per day students spend on social media. The survey results for the first-, second-, and third-period classes are as follows:

First period: 2, 4, 3, 1, 0, 2, 1, 3, 1, 4, 9, 2, 4, 3, 0

Second period: 3, 2, 3, 1, 3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2

Third period: 4, 5, 3, 4, 2, 3, 4, 1, 8, 2, 3, 1, 0, 2, 1, 3

Which is the best measure of center for first period and why?

Mean, because there are no outliers that affect the center***

Median, because there is 1 outlier that affects the center

Interquartile range, because there is 1 outlier that affects the center

Standard deviation, because there are no outliers that affect the center

Nope.

Hmm, then would it be D? Also, I am not guessing I am just unsure

No.

That's your second try -- and now you're on your own.

Study this site.

http://www.mathsisfun.com/definitions/outlier.html

Wait please! I need another website! I still don't necessarily understand. I don't see any outliers. I know that an outlier would affect the median

To determine the best measure of center for the first period, we need to consider the survey results. The options provided include the mean, median, interquartile range, and standard deviation.

The mean is calculated by adding up all the values and dividing by the total number of values. One way to determine if there are any outliers is to look for values that are significantly larger or smaller than the rest of the values.

In this case, the data points for the first period are: 2, 4, 3, 1, 0, 2, 1, 3, 1, 4, 9, 2, 4, 3, 0.

By calculating the mean, we get:

(2 + 4 + 3 + 1 + 0 + 2 + 1 + 3 + 1 + 4 + 9 + 2 + 4 + 3 + 0) / 15 = 2.6

To determine if there are any outliers, we can examine the data points. In this case, there are no data points that are significantly larger or smaller than the rest, so we can conclude that there are no outliers that affect the center.

Based on this information, the best measure of center for the first period is indeed the mean, as there are no outliers that would skew the results. Therefore, the correct answer is: Mean, because there are no outliers that affect the center.