Chemistry

The radioisotope radon-222 has a half-life of 3.8 days. How much of a 98.4 g sample of radon -222 would be left after approximately 19 days?

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  1. 98.4 * (1/2)^(19/3.8) = 3.075 g

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  2. Cf = Ci(e^-kt)
    Ci = 98.4 gms
    Cf = ?
    k = (0.693/3.8)days^-1 = 0.8663 da^-1
    t = 19 days
    Cf = Ci e^-kt
    Cf = 94.4gms e^-[(0.8663da^-1)(19da)]
    Cf = (94.4)(7.11 x 10^-8)gms
    Cf = 6.7 x 10^-6 gm remains

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  3. two errors, DrRebel:
    (0.693/3.8) ≠ 0.8663
    it was 98.4, not 94.4

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