# Maths

half of the sum of two number is 7,while one third of their product is 16,find the numbers

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1. (x+y)/2 = 7
xy/3 = 16

y=48/x

x+48/x = 14
x^2-14x+48 = 0
(x-6)(x-8) = 0

x and y are 6 and 8

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2. Thanks

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3. Not great

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4. x+y)/2 = 7
xy/3 = 16

y=48/x

x+48/x = 14
x^2-14x+48 = 0
(x-6)(x-8) =0
The numbers are 6 and 8
That's all

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5. thanks for solving my question

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