Maths

half of the sum of two number is 7,while one third of their product is 16,find the numbers

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  1. (x+y)/2 = 7
    xy/3 = 16

    y=48/x

    x+48/x = 14
    x^2-14x+48 = 0
    (x-6)(x-8) = 0

    x and y are 6 and 8

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  2. Thanks

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  3. Not great

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  4. x+y)/2 = 7
    xy/3 = 16

    y=48/x

    x+48/x = 14
    x^2-14x+48 = 0
    (x-6)(x-8) =0
    The numbers are 6 and 8
    That's all

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  5. thanks for solving my question

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