The worker pushes with a force of 10 N that points downward at an angle of 45° below the horizontal. What component of the force moves the crate forward?
I do not know how to set up this problem, so any help would be appreciated.
the component of the force that moves the crate (horizontal) is...the applied force, multiplied by the sine of the angle to the component
10N * sin(45º)
To determine the component of the force that moves the crate forward, we need to break down the force into its horizontal and vertical components.
First, let's visualize the situation. The force is being applied downward at an angle of 45° below the horizontal. This means that the angle between the force and the horizontal direction is 45°.
To find the horizontal component of the force, we can use trigonometry. The horizontal component is given by the equation:
Horizontal component = Force * cos(angle)
In this case, the force is 10 N and the angle is 45°.
Horizontal component = 10 N * cos(45°)
To solve this equation, we need to find the cosine of 45°. The cosine of 45° is √2/2.
Horizontal component = 10 N * (√2/2)
Simplifying this expression gives:
Horizontal component = 10 N * √2 / 2
Therefore, the horizontal component of the force is equal to 10 N * √2 / 2.
This horizontal component is what moves the crate forward.