Order the following solids from least (1) to greatest (3) volumes.
A rectangular pyramid whose base has an area of 60 in2 and whose height is 10 in. third
A rectangular prism with a length of 6 in, a width of 5 in, and a height of 10 in. first
A right cylinder with a diameter of 10 in and a height of 8 in. second
plz check if my answers are correct, sorry ^^;
A rectangular prism with a length of 6 in, a width of 5 in, and a height of 10 in. first
**** 300 in^3
A right cylinder with a diameter of 10 in and a height of 8 in. second
about (22/7)(25)(8) =
**** 628 in^3
THIS IS BIGGEST
A rectangular pyramid whose base has an area of 60 in2 and whose height is 10 in. third
**** 600 in^3
To order the solids from least to greatest volume, we need to calculate the volumes of each solid. The formula for the volume of each solid is as follows:
1. Rectangular pyramid: V = (1/3) * base area * height
2. Rectangular prism: V = length * width * height
3. Right cylinder: V = π * (radius)^2 * height
Let's calculate the volumes for each solid based on the given dimensions:
1. Rectangular pyramid:
Base area = 60 in²
Height = 10 in
V = (1/3) * 60 in² * 10 in
V = 200 in³
2. Rectangular prism:
Length = 6 in
Width = 5 in
Height = 10 in
V = 6 in * 5 in * 10 in
V = 300 in³
3. Right cylinder:
Diameter = 10 in
Radius = 10 in / 2 = 5 in
Height = 8 in
V = π * (5 in)^2 * 8 in
V = 200π in³ (approximately 628.32 in³)
Now, let's order the solids based on their volumes:
1. Rectangular pyramid: 200 in³
2. Right cylinder: 200π in³ (approximately 628.32 in³)
3. Rectangular prism: 300 in³
Therefore, the correct order from least (1) to greatest (3) volume is:
1. Rectangular pyramid
2. Right cylinder
3. Rectangular prism
So, your answers are not correct.