A diverging lens has a focal length of 17.3 cm.
An object 1.08 cm in height is placed 184 cm
in front of the lens.
Locate the position of the image.
Answer in units of cm.
1/p + 1/q = 1/f
Solve for q (the height doesn't enter in to it)
To find the position of the image formed by the diverging lens, we can use the lens formula:
1/f = 1/v - 1/u
Where:
f = focal length of the lens
v = distance of the image from the lens
u = distance of the object from the lens
Given:
f = -17.3 cm (negative sign indicates the lens is diverging)
u = -184 cm (negative sign indicates the object is in front of the lens)
Let's first convert the given measurements into positive values:
f = 17.3 cm
u = 184 cm
Substituting the values into the lens formula, we get:
1/17.3 = 1/v - 1/184
To simplify the equation, let's find the common denominator:
184/17.3 = 1/v
Now, cross multiply and solve for v:
(184)(17.3) = 17.3v
v = (184)(17.3) / 17.3
v ≈ 184 cm
Therefore, the position of the image formed by the diverging lens is approximately 184 cm away from the lens.