math plz help ;-;

1. Solve the system by any method:
2x-5y=-1
2x-y=1

How many solutions does the system of equations below have? Explain your answer.
y=3/5x-1
y=6/10x+3

plz help me ;-; i don't understand how to do this, sorry ;-;

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  1. 1. 2x-y=1 => y=2x-1 ...
    sub into equation 1 and solve for x ... 2x-5(2x-1)=-1 => 2x-10x+5=-1
    => 10x-2x=5+1
    => 8x=6 => x=(8/6)=(4/3)
    Sub x into either equation and solve for y ...
    2x-5y=-1
    => 2(4/3) - 5y = -1
    => 2.7 - 5y = -1
    => 2.7 + 1 = 5y
    => 3.7 = 5y
    => y = (3.7/5) = 0.74

    Same procedure for 2nd set... Solve one equation for x or y, sub into the 2nd equation and solve for the variable.

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  2. Since both equations contain 2x, the easiest way would be elimination, thus subtract them:

    -4y = -2
    y = -2/-4 = 1/2

    sub into the first:
    2x - 5(1/2) = -1
    2x = 5/2-1 = 3/2
    x = 3/4 ---------> x = 3/4 , y = 1/2

    #2
    y=(3/5_x-1
    y=6/10x+3 ----> y = (3/5)x + 3

    since you have two lines with the same slope, but different y-intercepts, you have two distinct parallel lines.
    Which of course cannot meet, so
    there is no solution

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