Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Calculus
Limits
Find the limit of sin4x/(sqrt(x)) as it approaches positive infinity.
1 answer
the numerator is bounded between -1 and 1, and the denominator approaches inf.
Looks like zero to me.
You can
ask a new question
or
answer this question
.
Related Questions
Which describes the end behavior of the graph of the function f(x)=-2x^3-5x^2+x?
a. f(x) approaches infinity as x approaches
Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)
If the limit as x approaches infinity (6x^2/200-4x-kx^2)=1/2, then k=
A. 3 B. -3 C. 12 D. -12 E. -3
Find the limit as x approaches infinity.
sqrt(81x^2 + x)− 9x. I've worked this two different ways and have gotten 0 and 1/9,
Fill in the blanks using the function below to describe the end behavior.
As x approaches - ∞, f(x) approaches _ a. infinity b.
F(x)=(2x-1)/ (|x| -3)
Rewrite f(x) as a piecewise function. Then find the limit as it approaches positive infinity and negative
F(x)=(2x-1)/ (|x| -3)
Rewrite f(x) as a piecewise function. Then find the limit as it approaches positive infinity and negative
The limit as x approaches infinity. (1)/(5^x)
The limit as x approaches 1. (1-x^3)/(2-sqrt(x^2-3)) Show your work thanks in
Find the limit as x approaches 0 [(sqrt(x+9))-3]/x
A. 0 B. 1 C. Infinity D. 1/3 E. None of these
What is the limit of the function as x approaches infinity?
4x^4 - 4^x Would the limit be positive infinity or negative infinity?