Write the formation equation for the ester that forms between propanoic acid and 1-pentanol. Include the names of the products and the structures for all substances involved.

CH3CH2COOH + HOCH2CH2CH2CH2CH3 -->

CH3CH2COOCH2CH2CH2CH2CH3 + H2O
The ester is pentyl propanoate

Thank you. Would this be the correct ester name propanoic acid + pentanol -> pentyl propoate + water ?

No, propoate is not correct.

Balanced equation for the esterification reaction that occurs between ethanol and propanoic acid in the presence of sulphuric acid

To write the formation equation for the ester that forms between propanoic acid and 1-pentanol, we need to understand the reaction and the structures of the substances involved.

First, let's identify the reactants:

1. Propanoic acid: It is a carboxylic acid with the molecular formula C3H6O2. The structure of propanoic acid is:

CH3CH2COOH

2. 1-Pentanol: It is an alcohol with the molecular formula C5H12O. The structure of 1-pentanol is:

CH3CH2CH2CH2CH2OH

Now, let's identify the products:

The reaction between propanoic acid and 1-pentanol results in an ester and water.

1. Ester: The ester formed is propyl pentanoate. Its structure can be determined by combining the alcohol portion of 1-pentanol (pentyl group) with the acid portion of propanoic acid (propyl group). The structure of propyl pentanoate is:

CH3CH2CH2COOCH2CH2CH3

2. Water (H2O) is also produced as a byproduct of the reaction.

Now, let's write the formation equation:

Propanoic acid + 1-pentanol → Propyl pentanoate + Water

or

CH3CH2COOH + CH3CH2CH2CH2CH2OH → CH3CH2CH2COOCH2CH2CH3 + H2O

This equation represents the reaction between propanoic acid and 1-pentanol to form propyl pentanoate and water.