Suppose that 9.6 mL of 1.5 M KOH(aq)

is transferred to a 250 mL volumetric flask
and diluted to the mark. It was found that
31.5 mL of this diluted solution solution was
needed to reach the stoichiometric point in a
titration of 9.6 mL of a phosphoric acid solution
according to the reaction
3 KOH(aq) + H3PO4(aq) →
K3PO4(aq) + 3 H2O(ℓ)
Calculate the molarity of the solution.
Answer in units of M.

(KOH) in the 250 mL volumetric flask is 1.5 M x 9.6/250 = approx 0.06 but that's an estimate.

mols KOH used = M x L = approx 0.06 x 0.0315 = approx 0.0018

Using the coefficients in the balanced equation, convert mols KOH to mols H3PO4. That's
0.0018 x (1 mol H3PO4/3 mol KOH = 0.0018 x 1/3 = ?
Then M H3PO4 = mols H3PO4/L H3PO4 = ?M

To find the molarity of the solution, we need to use the stoichiometry of the reaction and the volume of the solutions involved.

First, let's determine the number of moles of KOH reacted in the titration. We know that 31.5 mL of the diluted KOH solution was required to reach the stoichiometric point, and the initial volume of KOH solution used was 9.6 mL. Therefore, the moles of KOH reacted can be calculated as:

moles of KOH = (31.5 mL / 1000 mL) * (1.5 mol/L) * (9.6 mL / 1000 mL)

Next, let's use the stoichiometry of the reaction to calculate the moles of H3PO4 reacted. According to the balanced equation, the stoichiometric ratio between KOH and H3PO4 is 3:1. Therefore, the moles of H3PO4 reacted can be calculated as:

moles of H3PO4 = (moles of KOH) * (1 mol H3PO4 / 3 mol KOH)

Now that we know the moles of H3PO4 reacted in the titration, we can calculate its molarity using the volume of the H3PO4 solution that was titrated. In this case, the volume of the H3PO4 solution is 9.6 mL. Therefore, the molarity of the H3PO4 solution can be calculated as:

molarity of H3PO4 = (moles of H3PO4) / (volume of H3PO4 solution in L)

Finally, the molarity of the KOH solution is the same as the molarity of the H3PO4 solution because they react in a 1:1 stoichiometric ratio. Hence, the molarity of the KOH solution is:

molarity of KOH = molarity of H3PO4

By plugging in the values and calculating, you should get the molarity of the KOH solution in units of M.