A thin sheet of gold foil has an area of 2.98 cm2 and a mass of 6.20 mg. How thick is the sheet? The density of gold is 19, 300 kg/m3.

mass=density*volume=density*area*t

thickness=mass/density*area

= 6.20E-6kg/(19.300kg/m^3*(2.98cm^2)(m/100cm)^2

= 6.20E-6/(19.300*2.98E-4) m
=1.08mm

check my work, that seems pretty thick .

To find the thickness of the gold foil, we need to use its area, mass, and the density of gold.

First, let's convert the mass from milligrams (mg) to kilograms (kg):
mass = 6.20 mg = 6.20 × 10^(-6) kg

Next, let's calculate the volume of the gold foil using its mass and density:
density = 19,300 kg/m^3
volume = mass / density = (6.20 × 10^(-6) kg) / (19,300 kg/m^3)

Now, let's calculate the thickness of the gold foil using its volume and area:
area = 2.98 cm^2 = 2.98 × 10^(-4) m^2
thickness = volume / area = [(6.20 × 10^(-6) kg) / (19,300 kg/m^3)] / (2.98 × 10^(-4) m^2)

Calculating the thickness, we get:
thickness = [6.20 × 10^(-6) kg / 19,300 kg/m^3] / (2.98 × 10^(-4) m^2)

Therefore, the thickness of the gold foil is approximately the value obtained from the calculation above.

To find the thickness of the gold foil, we can use the formula:

Thickness = Mass / (Area * Density)

First, let's convert the area from cm^2 to m^2. Since 1 cm = 0.01 m, we have:

Area = 2.98 cm^2 = 2.98 x (0.01 m)^2 = 2.98 x 10^(-4) m^2

Next, let's convert the mass from mg to kg. Since 1 mg = 1 x 10^(-6) kg, we have:

Mass = 6.20 mg = 6.20 x (1 x 10^(-6) kg) = 6.20 x 10^(-6) kg

Now, let's substitute the values into the formula to find the thickness:

Thickness = (6.20 x 10^(-6) kg) / (2.98 x 10^(-4) m^2 * 19,300 kg/m^3)

Dividing the numerator and denominator by 19,300 kg/m^3, we get:

Thickness = (6.20 x 10^(-6) kg) / (2.98 x 10^(-4) m^2 / 19,300 kg/m^3)

Simplifying, we have:

Thickness = (6.20 x 10^(-6) kg) / (2.98 x 10^(-4) m^2 / 19,300 kg/m^3)
= (6.20 x 10^(-6) kg) x (19,300 kg/m^3) / (2.98 x 10^(-4) m^2)

Multiplying the numerator and denominator, we get:

Thickness = (6.20 x 10^(-6) kg) x (19,300 kg/m^3) / (2.98 x 10^(-4) m^2)
= 1.1974 x 10^(-4) kg⋅m / 2.98 x 10^(-4) m^2

Canceling out the common terms, we have:

Thickness = 1.1974 x 10^(-4) kg⋅m / 2.98 x 10^(-4) m^2
= 0.401 meters

Therefore, the thickness of the gold foil is 0.401 meters.