1) What would the slope be for a road that has a rise of 11m and a run of 100m?
a. 22 over 100
b. 11 over 100 (THS ONE)
c. 15 over 100
d. 30 over 100
2) What would the slope be for a road that has a rise of 5m and a run of 100m?
a. 0.05 (THIS ONE)
b. 0.25
c. 0.16
d. 0.02
3) What would the grade be for a road that has a rise of 11m and a run of 100m?
a. 15
b. 11 (THIS ONE)
c. 7
d. 3
4) What would the grade be for a road that has a rise of 5m and a run of 100m?
a. 4
b. 2
c. 5 (THIS ONE)
d. 3
5) Select the lowest terms for the ratio 9:27
a. 2:3
b. 3:9
c. 1:3 (THIS ONE)
d. 3:6
6) What is the slope of a line joining points (35, 27) and (35, 62)
a. 35 (THIS ONE)
b. undefined
c. 7
d. 0
7) Slope of a line joining points (2, 17) and (9, 17)
a. 12
b. undefined
c. 7
d. 0 (THIS ONE)
8) Solve for x in 6 over x = 4 over 8
a. 12
b. 2
c. 14
d. 8 (THIS ONE)
9) A line connecting the points (x, 12) and (12, 9) has a slope 1.4. Determine X.
a. 9
b. 10 (THIS ONE)
c. 7
d. 8
10. Steepest slope?
a. 0.4
b. undefined
c. 0.1
d. -1 over 7 (THIS ONE)
11. Flattest slope?
a. 7 over 9
b. 0 (THIS ONE)
c. undefined
d. 2 over 3
You don't know if I got any right?
No. I haven't taken a math class since high school -- some 65 years ago.
Your best bet is to simply put MATH in the School Subject line to get the attention of math tutors. When you put a specific tutor's name in the School Subject line, other tutors tend to skip the post.
Ok i figured out some that i got wrong but i'll that
1) To find the slope of a road, we need to divide the rise (vertical change) by the run (horizontal change). In this case, the rise is 11m and the run is 100m. So the slope is 11/100.
2) Similarly, for this road, the rise is 5m and the run is 100m. So the slope is 5/100, which simplifies to 0.05.
3) The grade of a road is the same as the slope, but expressed as a percentage. To convert the slope to a grade, we multiply it by 100. In this case, the slope is 11/100, so the grade is 11%.
4) For this road, the slope is 5/100, which simplifies to 0.05. Multiplying it by 100 gives a grade of 5%.
5) To simplify the ratio 9:27 to its lowest terms, we need to find the greatest common divisor (GCD) of 9 and 27, which is 9. Dividing both numbers by 9 gives us 1:3.
6) To find the slope of a line between two points, we use the formula (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points. In this case, the coordinates are (35, 27) and (35, 62). Since the x-values are the same, the denominator becomes 0, and the slope is undefined.
7) Similarly, for this line joining the points (2, 17) and (9, 17), the y-values are the same, making the denominator 0. So the slope is undefined.
8) To solve the equation 6 / x = 4 / 8, we cross-multiply. This gives us 6 * 8 = 4 * x. Simplifying, we have 48 = 4x. Dividing both sides by 4, we get x = 12.
9) We use the slope formula again: (y2 - y1) / (x2 - x1) = 1.4. Substituting the coordinates (x, 12) and (12, 9), we have (9 - 12) / (12 - x) = 1.4. Simplifying, we get -3 / (12 - x) = 1.4. Cross-multiplying gives us -3 = 1.4 * (12 - x). Distributing, we have -3 = 16.8 - 1.4x. Rearranging the equation, we get 1.4x = 19.8. Dividing both sides by 1.4, we find x = 19.8 / 1.4 = 14. So x = 14.
10) To determine the steepest slope, we look for the highest absolute value among the slopes given. In this case, the slope -1/7 has an absolute value of 1/7, which is smaller than the other options.
11) Similarly, to find the flattest slope, we look for the lowest absolute value among the slopes given. Here, the slope 0 has the lowest absolute value.