if a plate of car consists of two letters and four digits and one car chosen at random probabiliy the letters at the beginning and at the end

there are 6! total arrangement so it = 720

if the plate code is AS1234 and we have A (1234) S or S (1234) A for the numbers possible arrangement is 4!= 24 P(E)= 24/720=1/30
we have two ways P(E) will be 1/15.

The last answer is 1/30

we can use permutation to compute, there are 2 ways for the letters and 4 ways for the digits.

Totally there are 6 ways

2!4!/6!= 1/15

I need a detail explanation for this qs

How you know from 26 letter and ten numbers which is used to form this car plate? As I think the answers is incorrect.

3488

I need more explanation about how it com

To find the probability of the letters at the beginning and at the end of a car plate, we need to determine the total number of possible car plates and the number of car plates where the letters are at the beginning and the end.

Let's break down the process step by step:

1. Total number of possible car plates:
- We are given that a car plate consists of two letters and four digits.
- To calculate the total number of possible car plates, we need to consider the number of choices for each element (letter or digit) and multiply them together.
- There are 26 letters in the English alphabet, so the number of choices for each letter is 26.
- There are 10 digits (0-9), so the number of choices for each digit is 10.
- Since there are two letters, there are 26 * 26 = 676 possible letter combinations.
- And since there are four digits, there are 10 * 10 * 10 * 10 = 10,000 possible digit combinations.
- Hence, the total number of possible car plates is 676 * 10,000 = 6,760,000.

2. Number of car plates where the letters are at the beginning and the end:
- If the letters are at the beginning and the end, there is only one valid configuration for them.
- Since there are 26 choices for each letter, there are 26 * 26 = 676 possible configurations.

3. Probability calculation:
- The probability is given by dividing the number of favorable outcomes (plates with letters at the beginning and end) by the total number of possible outcomes (all car plates).
- Probability = Number of favorable outcomes / Total number of possible outcomes
- Probability = 676 / 6,760,000
- Simplifying the fraction, we get Probability = 1 / 10,000 or 0.0001 (or 0.01% in percentage form).

Therefore, the probability that the letters are at the beginning and at the end of a randomly chosen car plate is 0.0001 or 0.01%.

detail explaining

1/15