# maths

if a plate of car consists of two letters and four digits and one car chosen at random probabiliy the letters at the beginning and at the end

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1. there are 6! total arrangement so it = 720
if the plate code is AS1234 and we have A (1234) S or S (1234) A for the numbers possible arrangement is 4!= 24 P(E)= 24/720=1/30
we have two ways P(E) will be 1/15.

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2. The last answer is 1/30

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3. 1/15

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4. 3488

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5. I need a detail explanation for this qs

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6. How you know from 26 letter and ten numbers which is used to form this car plate? As I think the answers is incorrect.

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7. we can use permutation to compute, there are 2 ways for the letters and 4 ways for the digits.
Totally there are 6 ways

2!4!/6!= 1/15

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8. detail explaining

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9. I need more explanation about how it com

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