Ask questions and get helpful responses.

maths

if a plate of car consists of two letters and four digits and one car chosen at random probabiliy the letters at the beginning and at the end

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
  1. there are 6! total arrangement so it = 720
    if the plate code is AS1234 and we have A (1234) S or S (1234) A for the numbers possible arrangement is 4!= 24 P(E)= 24/720=1/30
    we have two ways P(E) will be 1/15.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. The last answer is 1/30

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  3. 1/15

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  4. 3488

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  5. I need a detail explanation for this qs

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  6. How you know from 26 letter and ten numbers which is used to form this car plate? As I think the answers is incorrect.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  7. we can use permutation to compute, there are 2 ways for the letters and 4 ways for the digits.
    Totally there are 6 ways

    2!4!/6!= 1/15

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  8. detail explaining

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  9. I need more explanation about how it com

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Respond to this Question

First Name

Your Response

Still need help? You can ask a new question.