The perimeter of a rectangle is 142m. The length is 5m more than twice the width. Find the dimensions.

length=
width=

2L+2W=142

L+5=2W

solve the system of equations

the second equation should be L=5+2W

my bad.

To find the dimensions of the rectangle, we need to set up an equation based on the given information.

Let's assume the width of the rectangle is "w". According to the problem, the length is 5m more than twice the width, so we can express the length as "2w + 5".

The perimeter of a rectangle is given by the formula: 2(length + width).

So, the equation for the perimeter of this rectangle can be written as:
2(2w + 5 + w) = 142

Now, we can simplify and solve for "w" to find the width:

2(3w + 5) = 142
6w + 10 = 142
6w = 142 - 10
6w = 132
w = 132/6
w = 22

Therefore, the width of the rectangle is 22m.

Now that we know the width, we can substitute it back into the expression for length to find the value of the length:

Length = 2w + 5
Length = 2(22) + 5
Length = 44 + 5
Length = 49

Therefore, the length of the rectangle is 49m.

The dimensions of the rectangle are:
Length = 49m
Width = 22m