Since the opening night, attendance at Play A has

increased steadily, while attendance at Play B first rose and then fell.
Equations modeling the daily attendance y at each play are shown below,
where x is the number of days since the opening night. On what day(S)
was the attendance the same at both plays? what was the attendance?

Play A: y = 16x + 150
Play B: y = -x^2 60x - 10

answer choices:

The attendance was the same on day 40. The attendance was 790 at both plays that day.
The attendance was the same on day 4. The attendance was 214 at both plays that day.
The attendance was the same on days 4 and 40. The attendance at both plays on those days was 214 and 790 respectively.
The attendance was never the same at both plays.
~~

Help is appreciated. I believe it is B or C

1.A

2.A
3.C
4.C
5.A
6.D
7.B
8.D
9.B
10.D
11.C
12.B
13.C
14.A
15.A
16.B
17.D
18.A
19.A
20.C
21.B
22.D
23.B
24.B
25.B
26.B
27.C
28.B
29.C
30.B

now go on ace that test YOU GOT THIS !!!!!!!!!!!!!!!!!!!!!!!!!

what was it

Nah that dude is wrong only 50% of his answers are right

To find the day and attendance when the attendance was the same at both plays (Play A and Play B), we need to find the value of x when the equations for Play A and Play B are equal.

First, let's set up the equation by equating the equations for Play A and Play B:

16x + 150 = -x^2 + 60x - 10

Now, let's simplify and rearrange the equation:

0 = -x^2 + 44x - 160

Next, let's solve the quadratic equation by factoring or using the quadratic formula. In this case, let's use factoring:

0 = (x - 10)(x - 16)

From this, we can see that x could be 10 or 16.

So, the attendance was the same on days 10 and 16. To find the attendance, we can substitute these values back into one of the original equations.

For Play A on day 10:
y = 16x + 150
y = 16 * 10 + 150
y = 160 + 150
y = 310

For Play A on day 16:
y = 16x + 150
y = 16 * 16 + 150
y = 256 + 150
y = 406

Therefore, the correct answer is:
The attendance was the same on days 10 and 16. The attendance at both plays on those days was 310 and 406, respectively.

So, option C is the correct answer.

Just put the equations into Desmos and find where they intersect. The answer to this one is C. They meet at the points, (4, 214) and (40, 790).

Algebra 1B huh? Plug in the numbers and check if it is true or false