A body is thrown vertically upwards at an initial velocity of 30m/s. Find the velocity after 2s and the time it takes to reach the maximum height.(TAKE g equal 10m/s2(square).
To find the velocity after 2 seconds and the time it takes to reach the maximum height, we can use the equations of motion for vertical motion.
Given:
Initial velocity (u) = 30 m/s
Acceleration due to gravity (g) = 10 m/s^2
Time (t) = 2 s
1. To find the velocity after 2 seconds (v):
Use the equation: v = u + gt
Substituting the given values:
v = 30 + (10)(2)
v = 30 + 20
v = 50 m/s
Therefore, the velocity after 2 seconds is 50 m/s.
2. To find the time it takes to reach the maximum height:
The maximum height is reached when the vertical velocity becomes zero (v = 0). At this point, the object starts to fall back down.
Use the equation: v = u + gt
0 = 30 + (10)(t_max)
-30 = 10t_max
t_max = -3 s
Since time cannot be negative, the negative value is discarded.
The time it takes to reach the maximum height is 3 seconds.
Therefore, the velocity after 2 seconds is 50 m/s and it takes 3 seconds to reach the maximum height.
To find the velocity after 2 seconds and the time it takes to reach the maximum height, we can use the equations of motion for vertical motion under constant acceleration.
Given:
Initial velocity (u) = 30 m/s (upwards)
Acceleration (g) = -10 m/s^2 (negative because it is acting downwards due to gravity)
Time (t) = 2 seconds
To find the velocity after 2 seconds:
We can use the equation v = u + gt, where v is the final velocity.
Substituting the given values:
v = 30 + (-10) * 2
v = 30 - 20
v = 10 m/s
Therefore, the velocity after 2 seconds is 10 m/s (upwards).
To find the time it takes to reach the maximum height:
At the highest point, the velocity becomes zero before it starts coming back down. This means the final velocity (v) is zero. We can use the equation v = u + gt and solve for t.
0 = 30 + (-10) * t
-30 = -10t
t = -30 / -10
t = 3 seconds
Therefore, it takes 3 seconds to reach the maximum height.
Note: Since the question didn't specify the direction of the velocity being upward or downward for the maximum height, we assumed it to be upward.