A 2.00 L flask is filled with propane gas (C3H8)at 1.00 atm and -15.0 Degrees Celsius. What is the mass of the propane in the flask?
To find the mass of the propane gas in the flask, we first need to determine the number of moles of propane using the ideal gas law equation:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)
1. Convert the temperature from Celsius to Kelvin:
T (Kelvin) = T (Celsius) + 273.15
T = -15.0 + 273.15 = 258.15 K
2. Rearrange the ideal gas law equation to solve for the number of moles:
n = PV / RT
Substituting the values:
n = (1.00 atm) x (2.00 L) / (0.0821 L·atm/mol·K) x (258.15 K)
3. Calculate the number of moles:
n = 0.159 mol
4. To find the mass of propane, we need to know the molar mass of propane (C3H8).
Carbon (C) has a molar mass of 12.01 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol.
Since there are 3 carbon atoms and 8 hydrogen atoms in propane, the molar mass is calculated as:
Molar mass of C3H8 = (3 x 12.01 g/mol) + (8 x 1.01 g/mol) = 44.11 g/mol
5. Calculate the mass of propane:
Mass = molar mass x number of moles
Mass = 44.11 g/mol x 0.159 mol
6. Calculate the mass of propane:
Mass = 7.00 g
Therefore, the mass of propane in the flask is 7.00 grams.
To find the mass of propane in the flask, we can use the ideal gas law equation:
PV = nRT
where:
P is the pressure of the gas (in Pa or atm)
V is the volume of the gas (in liters)
n is the number of moles of gas
R is the ideal gas constant (0.0821 L*atm/mol*K)
T is the temperature of the gas (in Kelvin)
First, let's convert the temperature from Celsius to Kelvin using the equation:
T(K) = T(°C) + 273.15
T(K) = -15.0°C + 273.15 = 258.15 K
Now, we can rearrange the equation to solve for the number of moles (n) using the given values of pressure, volume, and temperature:
n = (PV) / (RT)
n = (1.00 atm * 2.00 L) / (0.0821 L*atm/mol*K * 258.15 K)
n ≈ 0.096 mol
Next, we need to calculate the molar mass of propane (C3H8). The molar mass is the sum of the atomic masses of the elements in one mole of the substance. The atomic masses we will be using are found on the periodic table.
C3H8 molar mass:
(3 * molar mass of carbon) + (8 * molar mass of hydrogen)
The molar mass of carbon (C) is approximately 12.01 g/mol.
The molar mass of hydrogen (H) is approximately 1.01 g/mol.
Molar mass of C3H8:
(3 * 12.01 g/mol) + (8 * 1.01 g/mol)
= 36.03 g/mol + 8.08 g/mol
≈ 44.11 g/mol
Finally, to calculate the mass of propane in the flask, we can multiply the number of moles (n) by the molar mass of propane:
mass = n * molar mass
mass = 0.096 mol * 44.11 g/mol
mass ≈ 4.24 g
Therefore, the mass of propane in the flask is approximately 4.24 grams.
1.35gms.
From the Ideal Gas Law PV=nRT solve for moles CH4 = n = PV/RT = (1-Atm)(2.00-L)/(0.08206-L-Atm/mol-K)(273+15)K = 0.085-mole CH4... Convert to grams by multiplying by formula wt of CH4 = (0.085-mol)(16-gms/mol) = 1.35 gms.