A wire has a resistance of R. What will the wire's resistance be if it is stretched to four times its original length without changing the volume of the wire? (Express in

terms of R.)
R=V/I; 4R=V/I; R=V/(I/4)
I think this is right? help please.

Calculate p.d.at the e

To determine the wire's resistance if it is stretched to four times its original length without changing the volume, we need to understand the relationship between resistance and length.

Resistance is directly proportional to the length of the wire. This means that if the length of the wire increases, its resistance will also increase.

In this case, since the wire is stretched to four times its original length, we can say that the new resistance (R') will be equal to the original resistance (R) multiplied by a factor of four.

Therefore, the new resistance, R', can be expressed as:

R' = 4R

So, the wire's resistance will be four times its original resistance when it is stretched to four times its original length.