Rodney fa fair coin and chooses a ter tiles A, E, I, O AND U. He performs this experiment 50 times to determine the experimental probability that heds is tossed and the letter A is chosen. Whitch o following is st likely to be the experimental probability that Rodney determined?
A. 1/11
B. 9/25
C 4/7
D 2/3
I worked this out and I came up with 1/10 x 3/11 = 4/110 = 1/25 but this isn't an answer.
It would help if you proofread your questions before you posted them.
Where did you get 3/11?
From your data, I would get 1/5(letters) * 1/2(coin) = 1/10
To determine the experimental probability that heads is tossed and the letter A is chosen, you need to find the number of times both events occurred in the 50 trials and then divide it by the total number of trials.
Based on the information given, Rodney flips a fair coin and chooses a letter tile randomly out of A, E, I, O, and U. Let's break it down step by step:
- We first need to determine the probability of getting heads, which is 1/2 since a fair coin has two equally likely outcomes (heads or tails).
- The probability of choosing letter A out of the five available options is 1/5 since one out of five tiles is letter A.
To find the probability of both events happening together, we multiply the probabilities of each individual event:
1/2 (probability of getting heads) × 1/5 (probability of choosing letter A) = 1/10.
So, the probability of getting heads and choosing the letter A in a single trial is 1/10.
Next, we need to find the experimental probability over the 50 trials. To do this, we divide the number of successful outcomes (getting both heads and letter A) by the total number of trials.
However, the given answer choices do not match the calculated result of 1/25. It seems there may be an error in the options you provided. Please recheck the answer choices, or provide more information if available.