The Third angle of a Isosceles triangle is 16 degree less than the sum of the two equal angles. Find the three angles of the triangle
each of the equal angles ---- x
third angle ---- 2x - 16
x + x + 2x-16 = 180
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Math
Let's assume that the two equal angles of the isosceles triangle measure x degrees each.
According to the given information, the third angle is 16 degrees less than the sum of the two equal angles, so it would be (x + x) - 16 degrees.
The sum of the three angles of a triangle is always 180 degrees.
Therefore, we can set up the equation:
x + x + (x + x) - 16 = 180
Combining like terms:
4x - 16 = 180
Adding 16 to both sides of the equation:
4x = 196
Dividing both sides by 4:
x = 49
So, each of the two equal angles measures 49 degrees.
The third angle is (x + x) - 16 = (49 + 49) - 16 = 98 - 16 = 82 degrees.
Thus, the three angles of the isosceles triangle are 49 degrees, 49 degrees, and 82 degrees.
To find the three angles of an isosceles triangle, we'll start by assigning variables.
Let's say the two equal angles of the triangle are represented by 'x'. Since the third angle is 16 degrees less than the sum of the two equal angles, we can represent it as 'x + x - 16', which simplifies to '2x - 16'.
Now, we know that the sum of the three angles of any triangle is always 180 degrees. So, we can write an equation:
x + x + (2x - 16) = 180
Simplifying the equation:
4x - 16 = 180
Adding 16 to both sides:
4x = 196
Dividing both sides by 4:
x = 49
Now that we have found the value of 'x', we can substitute it back into our expressions to find each angle:
Two equal angles: x = 49 degrees
Third angle: 2x - 16 = 2(49) - 16 = 98 - 16 = 82 degrees
So, the three angles of the isosceles triangle are 49 degrees, 49 degrees, and 82 degrees.