Aaron's father is nine times as old as he is. One year ago, he was two years more than eleven as old as Aaron. Find Aaron's present age.
Aaron ---- x
his dad --- 9x
One year ago:
Aaron --- x-1
his dad --- 9x-1
9x-1 = 11(x-1) + 2
9x - 1 = 11x - 11 + 2
8 = 2x
x = 4
Aaron is 4
dad is 36
one year ago
Aaron -- 3
dad ---- 35 ---> was he 2 more than 11 times 3 ??
YES
To solve this problem, let's represent Aaron's present age as "x".
According to the problem, Aaron's father is nine times as old as Aaron, so his father's present age can be represented as "9x".
One year ago, Aaron's age was "x - 1", and his father's age was "9x - 1".
The problem also states that one year ago, Aaron's father was two years more than eleven times as old as Aaron. So we can set up the following equation:
9x - 1 = 2 + 11(x - 1)
Now, we can solve the equation to find Aaron's present age.
9x - 1 = 2 + 11x - 11
Combining like terms, we get:
9x - 11x = 2 - 11 + 1
-2x = -8
Dividing both sides by -2, we get:
x = 4
Hence, Aaron's present age is 4 years old.