What is the electrostatic force between one object with a charge of +5.0 × 10−6 C, and a second object with a charge of +2.0 × 10−6 C? The objects are 1.2 meters apart.
In a pith ball experiment, the two pith balls are at rest. The magnitude of the tension in each string is |T| = 0.55 N, and the angle between each string and a vertical line is θ = 27.33°. What are the values for the magnitudes of electrostatic force, Fq, and the gravitational force, Fg?
Fq=.55*sinTheta
Fg=.55*cosTheta
first q:
F=kqq/r^2=...
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elefor.html
To calculate the electrostatic force between two charged objects, we can use the formula for Coulomb's law:
F = k * (|q1| * |q2|) / r^2
Where:
- F is the electrostatic force between the objects,
- k is the electrostatic constant, approximately equal to 9 × 10^9 Nm^2/C^2,
- |q1| and |q2| are the magnitudes of the charges on the objects, and
- r is the distance between the objects.
In the first question, we are given that |q1| = +5.0 × 10^(-6) C, |q2| = +2.0 × 10^(-6)C, and the objects are 1.2 meters apart (r = 1.2 m). Plugging in these values into the formula, we have:
F = (9 × 10^9 Nm^2/C^2) * ((+5.0 × 10^(-6) C) * (+2.0 × 10^(-6) C)) / (1.2 m)^2
Simplifying the calculation, we get:
F ≈ 75 N
Therefore, the magnitude of the electrostatic force between the two objects is approximately 75 Newtons.
In the second question, we are given the magnitude of tension in each string (|T| = 0.55 N) and the angle between each string and a vertical line (θ = 27.33°) in a pith ball experiment. We need to find the magnitudes of the electrostatic force, Fq, and the gravitational force, Fg.
The tension, |T|, in the strings of the pith balls is equal to the sum of the magnitudes of electrostatic force, Fq, and the gravitational force, Fg:
|T| = |Fq| + |Fg|
Since the angle between each string and a vertical line is given, θ = 27.33°, we can find the vertical component of the tension, Tv, by using the equation:
Tv = |T| * cos(θ)
And since the pith balls are at rest, the vertical component of the tension should be equal to the gravitational force, Fg.
Therefore, we have:
|Fg| = Tv = |T| * cos(θ) = 0.55 N * cos(27.33°)
Calculating this, we find:
|Fg| ≈ 0.498 N
To find the magnitude of the electrostatic force, Fq, we can subtract the gravitational force from the tension:
|Fq| = |T| - |Fg| = 0.55 N - 0.498 N
Calculating this, we get:
|Fq| ≈ 0.052 N
Therefore, the magnitude of the electrostatic force, Fq, is approximately 0.052 Newtons, and the magnitude of the gravitational force, Fg, is approximately 0.498 Newtons.