Find the tensions in the given diagram. If the object supported weight is 800N
T4 70o T5 70o T3
C B
T1 T2
50o 30o
A
800N
To find the tensions in the given diagram, we can use the concept of forces and the principle of equilibrium.
1. Start by noting that there are three vertical forces acting on point C: the weight of the object (800N) and the tensions T4 and T5. These forces should add up to zero since the object is in equilibrium in the vertical direction.
So we have the equation: T4 + T5 - 800N = 0.
2. Next, consider the horizontal forces acting on point B. There are two tensions, T4 and T3, along with an unknown force acting to the right. Again, since the object is in equilibrium in the horizontal direction, the sum of these forces should be zero.
So we have the equation: T3 - T4*cos(70 o) = 0.
3. Now, let's analyze the forces at point A. There are three forces: tension T2, tension T3, and an unknown force acting to the left. The vertical components of these forces should add up to zero.
So we have the equation: T2*cos(30 o) + T3*sin(70 o) = 0.
4. Lastly, at point A, consider the horizontal forces. There are three forces: tension T1, tension T2, and an unknown force acting to the right. The sum of these forces should be zero.
So we have the equation: T1 + T2*sin(30 o) = 0.
5. Now, we have four equations with four unknowns (T1, T2, T3, and T4). Solve these equations simultaneously using algebraic methods to find the values of the tensions.
Note: The angles provided (30 o and 70 o) are necessary to calculate the horizontal and vertical components of the forces using trigonometry. The actual values of these angles are not provided in the question, so you can assume any convenient values for them or use algebraic expressions for the sine and cosine of these angles.