Calculate the number of moles of sodium oxide, Na2O, that should be produced when 11.50 moles of sodium, Na, react with oxygen gas
4Na + O2 ==> 2Na2O
11.50 mols Na x (2 molsl Na2O/4 mols Na) = 11.50 x (1/2) = ?
To calculate the number of moles of sodium oxide produced when 11.50 moles of sodium react with oxygen gas, you need to determine the mole ratio between sodium and sodium oxide in the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between sodium and oxygen gas to form sodium oxide is:
4 Na + O2 → 2 Na2O
From the equation, you can see that for every four moles of sodium (4 Na), two moles of sodium oxide (2 Na2O) are produced.
To find the number of moles of sodium oxide produced, you can set up a proportion using the mole ratio:
(2 moles of Na2O / 4 moles of Na) = (x moles of Na2O / 11.50 moles of Na)
Simplifying the equation gives:
x moles of Na2O = (2/4) * 11.50 moles of Na
x moles of Na2O = 5.75 moles of Na2O
Therefore, when 11.50 moles of sodium (Na) react with oxygen gas, the reaction will produce 5.75 moles of sodium oxide (Na2O).