A wire 20cm long carry current of 2A is placed perpendicular to a uniform magnetic field. If a force of 0.8N acts on it. Calculate the value of the magnetic field intensity B
To calculate the magnetic field intensity (B), we can use the formula for the magnetic force (F) acting on a current-carrying wire in a magnetic field:
F = BILsinθ,
where:
- F is the force acting on the wire,
- B is the magnetic field intensity,
- I is the current flowing through the wire,
- L is the length of the wire, and
- θ is the angle between the direction of the current and the magnetic field.
Here, we are given:
- F = 0.8 N (force acting on the wire),
- I = 2 A (current flowing through the wire), and
- L = 20 cm = 0.2 m (length of the wire).
Since the wire is placed perpendicular to the magnetic field, the angle θ between the current direction and the magnetic field is 90 degrees, making sinθ = 1.
Now we can rearrange the formula to solve for B:
B = F / (ILsinθ).
Substituting the given values:
B = 0.8 N / (2 A * 0.2 m * 1)
B = 0.8 N / 0.4 T
B = 2 T.
Therefore, the value of the magnetic field intensity B is 2 Tesla (T).