Tony works in a factory that produces 1,000 computers each day. When 50 computers were sampled, it was fount that 7 were defective. Estimate how many defective computers are made each day.

7/50 = ??

Multiply that answer times 100o to find about how many are defective each day.

I got 140.

Tony works in a factory that produces 1,000 computers each day. When 50 computers were sampled, it was found that 7 were defective. Estimate how many defective computers are made each day.

A. 140 computers
B. 7 computers
C. 169 computers
D. 265 computers

To estimate how many defective computers are made each day, we can set up a proportion:

defective/total = defective in sample/total in sample

Let d be the number of defective computers made each day. Then:

d/1000 = 7/50

We can cross-multiply to solve for d:

50d = 7000

d = 140

Therefore, the estimated number of defective computers made each day is 140, which is option A.

The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a consonant both times if the spinner is spun twice.

A circle is divided equally into three sections.· One of the sections is labeled with an upper E.
· One of the sections is labeled with an upper U.
· One of the sections is labeled with an upper N.
· An arrow originating from the center of the circle is pointing at the section labeled with upper U.
A. one-ninth
B. one-third
C. start fraction 5 over 9 end fraction
D. three-fourths

A yogurt shop offers 5 different flavors of frozen yogurt and 11 different toppings. How many choices are possible for a single serving of frozen yogurt with one topping?

A. 16 choices
B. 53 choices
C. 55 choices
D. 58 choices

There are 5 choices for the flavor of frozen yogurt and 11 choices for the topping. To find the total number of choices possible for a single serving with one topping, we can use the multiplication rule of counting:

total choices = (number of choices for frozen yogurt) x (number of choices for topping)

total choices = 5 x 11

total choices = 55

Therefore, there are 55 choices possible for a single serving of frozen yogurt with one topping, which is option C.

Sammy likes to mix and match her 4 necklaces, 2 bracelets, and 3 hats. The colors are listed in the table. On Monday, she randomly picks a bracelet, a necklace, and a hat. What is the probability of Sammy choosing a red necklace and yellow bracelet?

Necklace Bracelet Hat
Red Red Silver
Green Yellow Yellow
Gold Green
Silver
A. one-half
B. one-fifth
C. one-ninth
D. one-eighth

Sammy has 4 choices for her necklace, 2 choices for her bracelet, and 3 choices for her hat. The total number of ways she could choose one of each item is:

4 x 2 x 3 = 24

Out of these 24 possible outcomes, there is only one outcome where Sammy chooses a red necklace and a yellow bracelet, since there is only one red necklace and one yellow bracelet. Therefore, the probability of her choosing a red necklace and yellow bracelet is:

1/24

Therefore, the answer is not one of the answer choices given.

Here is a tree diagram showing all the possible outcomes of spinning the spinner twice:

```
C V
/ \ / \
C V C V
/ \ / \ / \ / \
C CC VC VV CV VC
/ \ / \
C V C V
```

Each branch represents a possible outcome of spinning the spinner twice. The letters "C" and "V" represent consonant and vowel, respectively. To find the probability that the spinner will land on a consonant both times, we can multiply the probabilities along the branches that lead to two consonants:

P(consonant twice) = P(CC) + P(CV) + P(VC)

Note that we also include the possibility of getting a consonant-vowel or vowel-consonant combination, as long as one of the letters is a consonant.

From the tree diagram, we can see that:

- P(CC) = (2/3)(2/3) = 4/9, since the probability of getting a consonant on the first spin is 2/3, and the probability of getting another consonant on the second spin, given that the first spin was a consonant, is also 2/3.
- P(CV) = (2/3)(1/3) = 2/9, since the probability of getting a consonant on the first spin is 2/3, and the probability of getting a vowel on the second spin, given that the first spin was a consonant, is 1/3.
- P(VC) = (1/3)(2/3) = 2/9, since the probability of getting a vowel on the first spin is 1/3, and the probability of getting a consonant on the second spin, given that the first spin was a vowel, is 2/3.

So:

P(consonant twice) = 4/9 + 2/9 + 2/9 = 8/9

Therefore, the probability that the spinner will land on a consonant both times if the spinner is spun twice is 8/9, which is not one of the answer choices provided.