Physics/Math

A machine carries a 5.0 kg package from an initial position of di = (0.50 m) i + (0.75 m) j + (0.20 m) k at t = 0 to a final position of df = (8.00 m) i + (11.0 m) j + (7.40 m) k at t = 13 s. The constant force applied by the machine on the package is F = (2.00 N) i + (4.00 N) j + (6.00 N) k.
(a) For that displacement, find the work done on the package by the machine's force.
(b) Also, find the power of the machine's force on the package.

Work= Force*displacement
Power= Work/time

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asked by Technoboi11

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