S and E had an equal amount of . After s had received an additional amount of money that is equal to what she had and E spent $4, S had $40 more than E. How much money did E have at first?
In Each Of The Following O Is Centre Of The Circle.In Each Figure, Identify Which Angles Are: Supplemetary 2 Right Angles. 3 Congruent Angles.
S = E
2S = 2E = E - 4 + 40
First, if you have a question, it is much better to put it in as a separate post in <Post a New Question> rather than attaching it to a previous question, where it is more likely to be overlooked.
Second, there are no figures. You cannot copy and paste here.
To solve this problem, we can break it down step by step:
1. Let's assume that both S and E initially had x dollars, as stated in the problem.
2. After S received an additional amount of money that is equal to what she had, S now has x + x = 2x dollars.
3. On the other hand, E spent $4, so E now has x - 4 dollars.
4. According to the problem, after these transactions, S had $40 more than E. This can be expressed as 2x - (x - 4) = 40.
5. Simplifying the equation, we have 2x - x + 4 = 40.
6. Combining like terms, we get x + 4 = 40.
7. Subtracting 4 from both sides, we find that x = 36.
Therefore, E initially had x = $36.