graph and show solution for y = Ix+2I and translated y =- IxI

To graph and show the solution for y = |x + 2|, we can start by understanding the properties of the absolute value function.

The absolute value function (|x|) represents the distance of a number from zero on a number line. It always returns a non-negative value. In this case, we have y = |x + 2|, which means the distance of (x + 2) from zero.

To graph this equation, we can consider different values of x and evaluate y = |x + 2|.

Let's begin with x = -4:
y = |-4 + 2|
y = |-2|
y = 2

So, when x = -4, y = 2.

Similarly, we can choose more values of x and find the corresponding values of y to plot the graph.

x = -3:
y = |-3 + 2|
y = |-1|
y = 1

x = -2:
y = |-2 + 2|
y = |0|
y = 0

x = -1:
y = |-1 + 2|
y = |1|
y = 1

x = 0:
y = |0 + 2|
y = |2|
y = 2

x = 1:
y = |1 + 2|
y = |3|
y = 3

x = 2:
y = |2 + 2|
y = |4|
y = 4

Now, we can plot these points on a graph and connect them to form the graph of y = |x + 2|.

Here is the graph:

| *
| *
| *
| *
-----|----------------------
| *
| *
| *
| *
| *

Now let's move on to the next equation, y = -|x|. This equation represents the negative value of |x|.

To graph y = -|x|, we can evaluate different values of x and find the corresponding values of y.

Taking similar values of x as before, we have:

x = -4:
y = -|-4|
y = -4

x = -3:
y = -|-3|
y = -3

x = -2:
y = -|-2|
y = -2

x = -1:
y = -|-1|
y = -1

x = 0:
y = -|0|
y = 0

x = 1:
y = -|1|
y = -1

x = 2:
y = -|2|
y = -2

Plotting these points on a graph and connecting them, we get the graph for y = -|x|:

| *
| *
| *
| * *
-----|----------------------
| *
| *
| *
| *
| *

So, the graphs of y = |x + 2| and y = -|x| are plotted and shown here.