A 45.0 g piece of copper wire is heated. And the temperature of the wire changes from 21.0 degrees C to 88.0 degrees C. The amount of heat absorbed is 280.6 cal. Find the specific heat of Copper. SHOW your work.
Please help! I have no Idea where to start or what to do
q = mass x specific heat x (Tfinal-Tinitial)
280.6 = 45 x sp.h. x (88-21).
To find the specific heat of copper, we can use the equation Q = mcΔT, where Q represents the amount of heat absorbed, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature.
In this case, we are given the following information:
- Q = 280.6 cal
- m (mass of copper wire) = 45.0 g
- ΔT (change in temperature) = 88.0 degrees C - 21.0 degrees C = 67.0 degrees C
Now we can substitute the values into the equation and solve for the specific heat (c):
Q = mcΔT
280.6 cal = (45.0 g) * c * (67.0 degrees C)
To isolate c, divide both sides of the equation by (45.0 g) * (67.0 degrees C):
c = 280.6 cal / (45.0 g * 67.0 degrees C)
c ≈ 0.1176 cal/g°C
Therefore, the specific heat of copper is approximately 0.1176 cal/g°C.