Two rectangles have the same width. One is 12 units long and the other is 8 units long. The area of the first rectangle is 320 square units more than the area of the second rectangle. Find the width of each rectangle.

answer:80 units

Right, the answer is 80 units

To solve this problem, we can use the formula for the area of a rectangle: area = length × width.

Let's assume the width of both rectangles is "w" units. Then we have:

Area of the first rectangle = 12w
Area of the second rectangle = 8w

Given that the area of the first rectangle is 320 square units more than the area of the second rectangle, we can set up the following equation:

12w = 8w + 320

Now we can solve for the width "w":

12w - 8w = 320
4w = 320
w = 320 / 4
w = 80

Therefore, the width of each rectangle is 80 units.

Let the width be w

area of first = 12w
area of 2nd = 8w

12w - 8w = 320

carry on