The perimeter of a rectangle is 300 feet the width of the rectangle is 10 feet more than the length what is the width of the rectangle ?
P = 2L + 2W
300 = 2L + 2(L + 10)
300 = 4L + 20
280 = 4L
70 = L
To find the width of the rectangle, we'll use the given information that the perimeter is 300 feet and the width is 10 feet more than the length.
Let's assign variables to the length and width of the rectangle. We can represent the length as 'L' and the width as 'W'.
According to the given information, we can set up two equations:
1) Perimeter of a rectangle: 2(length + width) = 300
This equation represents the perimeter formula, where we multiply the sum of the length and width by 2 to get the perimeter.
2) Width = Length + 10
This equation represents the relationship between the width and length, where the width is 10 feet more than the length.
Now, we can solve for the width of the rectangle by substituting the second equation into the first equation.
Substituting 'Width' with 'Length + 10' in the first equation, we get:
2(Length + (Length + 10)) = 300
Simplifying the equation, we have:
2(2Length + 10) = 300
4Length + 20 = 300
Next, let's isolate 'Length' by subtracting 20 from both sides:
4Length = 300 - 20
4Length = 280
Now, divide both sides of the equation by 4 to solve for 'Length':
Length = 280 / 4
Length = 70
So, the length of the rectangle is 70 feet.
To find the width, substitute the length back into the equation:
Width = Length + 10
Width = 70 + 10
Width = 80
Therefore, the width of the rectangle is 80 feet.