Box A has 3 red marbles and2 yellow marbles. Box B has 2 red marbles and 1 yellow marble. If you have to pick a re marble to win a prize and you can not look in the box, which box would give you the best chance of winning the prize?

i would look in the b box beacuse if you have two red marbles in it and you have one yellow on so u have to ovili get the red on and you would win and athen you would have to thank me becaus ei would have helped you any wayan that is y i am in thehigh school or in middle school i should say

I would pick Box B because you have a 60% chance of picking a red marble in Box A and you have a 66.6% chance of picking a red marble in Box B.

I agree with Ben

Box A has 5 marbles, three of which are red
Therefore the probability of drawing a red from box A is 3/5 = .6
Box B has three marbles, two of which are red.
Therefore the probability of drawing a red from box B is 2/3 = .66666666.....

To determine which box would give you the best chance of winning the prize, you need to calculate the probability of picking a red marble from each box.

For Box A:
Total marbles = 3 red marbles + 2 yellow marbles = 5 marbles
Probability of picking a red marble from Box A = 3 red marbles / 5 marbles = 3/5 = 0.6 or 60%

For Box B:
Total marbles = 2 red marbles + 1 yellow marble = 3 marbles
Probability of picking a red marble from Box B = 2 red marbles / 3 marbles ≈ 0.666 or 66.6%

Comparing the probabilities, we find that Box B has a higher probability of picking a red marble (66.6%) compared to Box A (60%). Therefore, Box B would give you a better chance of winning the prize.