There are 3000 bacteria in a day, if the number of bacteria double per 2 days , how many bacteria can we expect to have in 15 days??

My result was 44,999.99 which if rounded is 45,000,am i accurate? ?

amount = 3000(2)^(t/2) , where t is the number of days

= 3000(2)^(15/2)
= 543,058

How did you get 45,000 ?

To find out how many bacteria can be expected after 15 days, we need to calculate the exponential growth of the bacteria population.

Since the number of bacteria doubles every 2 days, after 2 days we would have 3000 x 2 = 6000 bacteria. After 4 days, we would have 6000 x 2 = 12,000 bacteria. And so on.

In general, the formula for exponential growth is:

N(t) = N0 * (2^(t/d))

Where:
N(t) is the final number of bacteria after time t,
N0 is the initial number of bacteria,
t is the total time, and
d is the doubling time (which is 2 days in this case).

Let's calculate the number of bacteria after 15 days using this formula:

N(15) = 3000 * (2^(15/2))
N(15) = 3000 * (2^7.5)
N(15) ≈ 45,254.83

So, the expected number of bacteria after 15 days is approximately 45,254.83. Rounding this to the nearest whole number, we get 45,255.

Therefore, your result of 44,999.99 rounded to 45,000 is very close to the accurate answer of approximately 45,255 bacteria.