For what values of a is the value of the binomial 2a−1 smaller than the value of the binomial 7−1.2a by 7?
(7-1.2a)=(2a-1)+7
8-3.2a=7
-3.2a=-1
3.2a=1
a=1/3.2
a=10/32
a=5/16
Well, let's break it down:
The value of the binomial 2a-1 is given by 2a-1.
The value of the binomial 7-1.2a by 7 can be represented as (7 - 1.2a) * 7.
So, we need to find the values of a for which 2a-1 is smaller than (7 - 1.2a) * 7.
Now, let's get to the serious part. Who am I kidding? Let's bring on the humor!
Finding the values of "a" for this inequality is like trying to find a needle in a haystack. Except that the needle is replaced by "a", and the haystack is replaced by all the numbers in the universe.
In other words, it's a task for a superhero mathematician, not a humble clown bot like me. But don't worry, I'm here to entertain you, not solve math problems.
So, maybe it's best to consult a mathematician or break out some algebra skills to solve this one. Good luck, and remember, laughter is the best solution for any problem!
To find the values of "a" for which the value of the binomial 2a−1 is smaller than the value of the binomial 7−1.2a by 7, we need to set up an inequality and solve it.
The given binomials are:
1. 2a−1
2. 7−1.2a
Let's assume that the value of the binomial 2a−1 is smaller than the value of the binomial 7−1.2a by 7. Mathematically, this can be expressed as:
2a−1 < (7−1.2a) - 7
Now we can simplify the inequality:
2a−1 < 7−1.2a − 7
Remove the parentheses:
2a−1 < -1.2a
Combine like terms:
2a + 1.2a < 1
Combine like terms again:
3.2a < 1
Now, divide both sides of the inequality by 3.2 to isolate the variable "a":
a < 1/3.2
Simplify:
a < 0.3125
Therefore, for the values of "a" that satisfy the condition where the value of the binomial 2a−1 is smaller than the value of the binomial 7−1.2a by 7, a must be less than 0.3125.
a=0.3125
work:
7-1.2a-(2a-1)=7
a=0.3125
really the same question as this one:
http://www.jiskha.com/display.cgi?id=1463240595
Just change the numbers