A researcher tagged 40 giant turtles in 2008. In 2009 she returned and captured 50 turtles, 16 of which were tagged. in 2010 she returned again and captured 30 turtles 8 of which were tagged.
a: Use a proportion to estimate the turtle population for 2009
b: Use a proportion to estimate the turtle population for 2010
In 2009, 16/50 = 32% of the population was tagged, making the population 40/.32 = 125 (P/40 = 50/16)
In 2010, 8/30 = 26.7% of the population was tagged. So, the population is about 150 (P/40 = 30/8)
Why did you switch names?
http://www.jiskha.com/display.cgi?id=1463155297
bc My old name wasn't really a name
i don't understand steves one
To estimate the turtle population for 2009 and 2010, we can use the method of proportion. We know the number of tagged turtles in each year and can assume that the proportion of tagged turtles to the total population remains constant over time.
a) To estimate the turtle population for 2009:
We know that in 2008, 40 turtles were tagged.
In 2009, the researcher captured 50 turtles, and 16 of them were tagged.
To estimate the turtle population for 2009, we can set up a proportion:
tagged turtles in 2009 / total turtles in 2009 = tagged turtles in 2008 / total turtles in 2008
16 / 50 = 40 / x
To solve for x, we can cross-multiply and then divide:
16x = 50 * 40
16x = 2000
x = 2000 / 16
x ≈ 125
Therefore, we can estimate the turtle population for 2009 to be around 125 turtles.
b) To estimate the turtle population for 2010:
We know that in 2010, the researcher captured 30 turtles, with 8 of them being tagged.
To estimate the turtle population for 2010, we can set up a proportion:
tagged turtles in 2010 / total turtles in 2010 = tagged turtles in 2008 / total turtles in 2008
8 / 30 = 40 / x
Again, we can cross-multiply and then divide:
8x = 30 * 40
8x = 1200
x = 1200 / 8
x = 150
Therefore, we can estimate the turtle population for 2010 to be around 150 turtles.