The equation f(x) = 4x^2 − 16x + 9 represents a parabola. What is the vertex of the parabola?
(2, −7)
(−2, 57)
(4, 9)
(−4, −137)
is it a pls helpme
x = =-b/2a
b = -16 so -b = 16
a = 4
x= 16/8 = 2
Find y by substituting
To find the vertex of a parabola given by the equation f(x) = 4x^2 − 16x + 9, you can use the formula x = -b / (2a), where a, b, and c are the coefficients of the quadratic equation in standard form: ax^2 + bx + c = 0.
In this case, a = 4 and b = -16. Plugging these values into the formula, we get x = -(-16) / (2*4) = 16 / 8 = 2.
To find the y-coordinate of the vertex, substitute this x-value back into the equation: f(2) = 4(2)^2 − 16(2) + 9 = 16 - 32 + 9 = -7.
So the vertex of the parabola is (2, -7).
Therefore, the correct answer is (2, −7)
the vertex on the x axis is 1/2 the way between roots...
4x^2-16x + 9
x=(16+-sqrt(256-4*36))/8
= 2 +-sqrt(112) /8
so half way will be when x is
2, so the first answer is correct