Hi, just a short question. How do i find the x intercepts for the equation y=-2x^3+1 ?
I tried to let y equal zero but i could only get as far as x^3=1/2
please help!
x^3 = 1/2 is correct. There is only ine x-intercept. It is where x = (1/2)^(1/3) which means the cube root of 1/2.
x = 0.7937
thank you soooooooo much!
To find the x-intercepts for the equation y = -2x^3 + 1, you follow these steps:
Step 1: Set y = 0 because x-intercepts occur when y = 0, meaning they are the points where the graph intersects the x-axis.
0 = -2x^3 + 1
Step 2: Rearrange the equation to isolate x^3.
2x^3 = 1
Step 3: Divide both sides by 2 to solve for x^3.
x^3 = 1/2
Step 4: To solve for x, you need to take the cube root of 1/2.
x = (1/2)^(1/3)
Using a calculator or computer software, you can calculate the cube root to find that x is approximately 0.7937.
So, the x-intercept for the equation y = -2x^3 + 1 is roughly x = 0.7937.