evaluate 4x^2(2x+x^3y)+x^y for x = 5 and y=0
Evaluate 4 (x/5)^2+3 when c =20
Ms.sue help
SOME ONE PLEASE HELP QUICKLY
4x^2(2x+x^3y)+x^y = 8x^3 + (4x^5)y + x^y
When multiplying/dividing, exponents are added/subtracted respectively.
Anything to the zero power = 1
4x^5 * zero = zero
So you are left with 8x^3 +1 = ?
evaluate 4x^2(2x+x^3y)+x^y for x = 5 and y=0
4x^2(2x+x^3y)+x^y
= 4(5^2)(10 + 5^0) + 5^0
= 100( 10 + 1) + 1 , .............. anything^0 = 1
= 1100
To evaluate the expression 4x^2(2x+x^3y)+x^y for x = 5 and y = 0, follow these steps:
Step 1: Substitute the given values of x and y into the expression.
4(5)^2(2(5)+(5)^3(0))+5^0
Step 2: Simplify the expression inside the parentheses.
4(25)(10+0)+1
Step 3: Simplify any exponent expressions.
4(25)(10)+1
Step 4: Perform the multiplication.
(4)(25)(10)+1
Step 5: Continue the multiplication.
(100)(10)+1
Step 6: Perform the final multiplication.
1000+1
Step 7: Add the final terms.
1001
Therefore, the value of the expression 4x^2(2x+x^3y)+x^y, when x = 5 and y = 0, is 1001.
Now let's move on to evaluating the expression 4(x/5)^2+3 when c = 20.
To evaluate this expression, follow these steps:
Step 1: Substitute the given value of c into the expression.
4(20/5)^2+3
Step 2: Simplify the expression inside the parentheses.
4(4)^2+3
Step 3: Simplify the exponent expression.
4(16)+3
Step 4: Perform the multiplication.
64+3
Step 5: Add the final terms.
67
Therefore, the value of the expression 4(x/5)^2+3, when c = 20, is 67.