The angle of elevation of the top of a radio mast from a point 53 metres from its base on level ground is 61 degrees.What is the height of the mast to the nearest 5 metres

draw a vertical line to represent the radio mast,and then a horizontal 53m away from the radio mast.and then also a diagonal line from the angle of elevation to the top of the radio mast

then
tan63=h/53
find h?

I am sure collins meant to say

tan 61° = h/53 , just a typo

Tan61 degrees= h/53

= 95.61

Tan

Ybgvtiby bt

To find the height of the mast, we can use trigonometry. The given information tells us that the angle of elevation is 61 degrees and the distance from the base of the mast to the observer is 53 meters.

Let's call the height of the mast "h". We can use the tangent function to set up an equation:

tan(61 degrees) = h / 53

To solve for h, we can rearrange the equation:

h = 53 * tan(61 degrees)

Now, let's calculate the height using this equation:

h ≈ 53 * tan(61 degrees)
≈ 53 * 1.907
≈ 101.171

Therefore, the height of the mast is approximately 101.171 meters. However, we need to round the answer to the nearest 5 meters. The nearest 5-meter increment would be 100 meters.

So, the height of the mast, rounded to the nearest 5 meters, is 100 meters.

You do not no the answer