hi can someone tell me how to put 18/48 in lowest terms and 16/40 in lowest terms
18/48
Let's start by dividing the numerator and denominator by 2
18/48 = 9/24
That's still not the lowest terms. Now let's divide by 3.
9/24 = 3/8
I could have saved some time by dividing by 6 the first time.
Now you can do the same with 16/40. What is the lowest terms for that fraction?
Keep dividing both the numerator and denominator by 2 or 3 or any other divisor they have in common until you can't divide evenly any more.
18/48 = 9/24 = 3/8
16/40 = ?
would it be 2/5
Right! 16/40 = 2/5
THANK YOU
You're welcome.
Of course! To put a fraction in its lowest terms, we need to simplify it by dividing both the numerator (top number) and the denominator (bottom number) by their greatest common divisor (GCD).
Let's start with the fraction 18/48.
Step 1: Find the GCD of 18 and 48.
To find the GCD, you can use various methods like factoring or using the Euclidean algorithm. In this case, we can see that both 18 and 48 are divisible by 6, so the GCD is 6.
Step 2: Divide both the numerator and the denominator by the GCD.
18 ÷ 6 = 3
48 ÷ 6 = 8
Therefore, 18/48 in its lowest terms is 3/8.
Now, let's move on to the fraction 16/40.
Step 1: Find the GCD of 16 and 40.
Again, we can see that both 16 and 40 are divisible by 8, so the GCD is 8.
Step 2: Divide both the numerator and the denominator by the GCD.
16 ÷ 8 = 2
40 ÷ 8 = 5
Therefore, 16/40 in its lowest terms is 2/5.
I hope this explanation helps you in simplifying fractions to their lowest terms!