a stone is projected from a catapult with a speed of 50m/s and it attains a height 100m calculate d angle of projection
recall that the max height is found using
h = (v sin(theta))^2 / 2g
so, plug in your numbers
I will try
To calculate the angle of projection, we need to make use of the equations of motion for projectile motion. In this case, we know the initial velocity (50 m/s) and the maximum height reached (100 m).
First, let's analyze the vertical motion of the stone. At the maximum height, the velocity in the vertical direction will be zero. We can use the equation for vertical velocity:
v_vertical = v_initial * sin(theta)
where v_vertical is the vertical component of the initial velocity, v_initial is the initial velocity of the stone, and theta is the angle of projection.
Since the vertical velocity is zero at the maximum height, we can rewrite the equation as:
0 = v_initial * sin(theta)
Now, we can solve for theta:
sin(theta) = 0 / v_initial
sin(theta) = 0
Since the sine function is zero for angles other than 0 degrees, we can conclude that theta = 0 degrees.
So, the angle of projection in this case is 0 degrees.