Solve (10x^3+30x-20)÷(-5x+5)
2x^2-2x+4
-2x^2-2x-4
-2x^2+2x+4
2x^2+2x-4
you have
5(2x^3+6x-4) / -5(x-5)
= -(2x^3+6x-4)/(x-5)
a little synthetic division shows that it does not divide evenly. I suspect a typo.
However, it is clear that only B or C could work, even after the typos is fixed.
Youre right its supposed to be
(-10x^3+30x-20)÷(-5x+5)
so, now it's down to A or D.
Do the math...
To solve the expression (10x^3 + 30x - 20) ÷ (-5x + 5), we can use long division. Here's how to do it step by step:
Step 1: Write the expression in long division format:
____________________
(-5x + 5) | (10x^3 + 30x - 20)
Step 2: Divide the first term of the dividend by the first term of the divisor:
2x^2
Step 3: Multiply the quotient (2x^2) by the divisor (-5x + 5):
2x^2 * (-5x + 5) = -10x^3 + 10x^2
Step 4: Subtract the result from the dividend:
(10x^3 + 30x - 20) - (-10x^3 + 10x^2) = 10x^3 + 30x - 20 + 10x^3 - 10x^2
= 20x^3 + 20x^2 + 30x - 20
Step 5: Bring down the next term from the dividend:
20x^3 + 20x^2 + 30x - 20
Step 6: Repeat steps 2-5 until there are no more terms to bring down.
Step 7: The last quotient obtained will be the expression:
Quotient = 2x^2 - 2x + 4
Therefore, the correct answer is 2x^2 - 2x + 4.