A buoy in a lake is 20 yards from Dock 1 and 20 yards from Dock 2. To the nearest tenth of a centimeter of a yard; how far apart are the two docks?

Please check my answer. Thank you.
id it 17.3 yards?? I'm lost

could be, depending on where the docks are.

The docks could be anywhere from 0 to 40 yards apart.

To find the distance between the two docks, we can use the Pythagorean theorem. Let's label the distance between Dock 1 and the buoy as "x" and the distance between Dock 2 and the buoy as "y". The distance between the two docks is then the hypotenuse of a right triangle with sides x and y.

Given that x = 20 yards and y = 20 yards, we can use the Pythagorean theorem to find the distance between the two docks (d):

d = sqrt(x^2 + y^2)

d = sqrt(20^2 + 20^2)

d = sqrt(400 + 400)

d = sqrt(800)

Now, let's approximate the value of d to the nearest tenth of a centimeter of a yard:

d ≈ 28.3 yards

Therefore, the distance between the two docks is approximately 28.3 yards (to the nearest tenth of a centimeter of a yard).

Your answer of 17.3 yards is not correct.